Answer:
The value would be 3.
Step-by-step explanation:
[tex]\tt{x=3}[/tex], [tex]\tt{y=-3}[/tex], [tex]\tt{c=\frac{7}{3}}[/tex]
[tex]\large\text{$\tt{\frac{5x-2y}{3c}=\frac{5(3)-2(-3)}{3(\frac{7}{3})}=\frac{15+6}{7}=\frac{21}{7}}=\boxed{\tt{3}}$}[/tex]
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