Answer:
The result is s² - 6s + 9.
Step-by-step explanation:
Step 1:
Square the first term.
- [tex]\tt{(s-3)^2=s^2}[/tex]
Step 2:
Multiply the product of the first and last terms by 2.
- [tex]\tt{(s-3)^2=s^2+2(s)(-3)=s^2-6s}[/tex]
Step 3:
Square the last term.
- [tex]\tt{(s-3)^2=s^2-6s+(-3)^2=s^2-6s+9}[/tex]
Complete Solution:
- [tex]\tt{(s-3)^2=s^2+2(s)(-3)+(-3)^2}=\boxed{\tt{s^2-6s+9}}[/tex]
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