Sagot :
Problem:
If p varies inversely as the square of q and p = 3 when q = 4, find p when q = 16
Solution:
k = constant of variation
p = k/q²
3 = k/4²
3 = k/16
3(16) = k
k = 48
p = k/q²
p = 48/16²
p = 48/256
p = 3/16
k = constant of variation
p = k/q²
3 = k/4²
3 = k/16
3(16) = k
k = 48
p = k/q²
p = 48/16²
p = 48/256
p = 3/16