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The area of circular table is A(×) =ײ-6×+9 square units. What polynomial represents the side of circular table?

a. s(×) =×+ unit
b. s(×) =×-3 unit
c. s(×) =-6 unit
d. s(×) =+9 unit​


Sagot :

Answer:

[tex]b. \: s(x) = x - 3 \: unit[/tex]

Step-by-step explanation:

[tex]area = {s}^{2} [/tex]

[tex] {x}^{2} - 6x + 9 = {x}^{2} [/tex]

[tex] {(x - 3)}^{2} = {s}^{2} \\ {s}^{2} = {(x - 3)}^{2} \\ \sqrt{ {s}^{2} } = \sqrt{ {(x - 3)}^{2} } \\ s = x - 3[/tex]

Note:

Correction: It is square not circular.