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4. If x varies as the square of y and inversely as z and x = 12 when y = 3 and z = 6, find x
when y = 9 and z= 6.​


Sagot :

Answer:

x=108

Step-by-step explanation:

[tex]x = \frac{k{y}^{2} }{z} \\ \\ 12 = \frac{k {3}^{2} }{6} \\ \\ 12 = \frac{9k}{6} \\ \\ 9k = 72 \\ \\ \frac{9k}{9} = \frac{72}{9} \\ \\ k = 8 \\ \\ \\ [/tex]

[tex]x = \frac{8 ({9}^{2}) }{6 } \\ \\ x = \frac{648}{6} \\ \\ x = 108[/tex]