Sagot :
Problem:
Suppose "a varies inversely as b and a is 10 when b is 5". Determine the equation of variation.
Solution:
a = k/b
10 = k/5
10(5) = k
k = 50
a = 50/b → equation of variation
a = k/b
10 = k/5
10(5) = k
k = 50
a = 50/b → equation of variation