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find the first term of the arithmetic sequence given that a8 =54 and a9=60​

Sagot :

Answer:

a1= 12

Step-by-step explanation:

d=a2-a1

therefore,

d=a9-a8

d=60-54

d=6

a7=a8-d

a7=54-6

a7=48

a6=a7-d

a6=48-6

a6=42

a5=a6-d

a5=42-6

a5=36

a4=a5-d

a4=36-6

a4=30

a3=a4-d

a3=30-6

a3=24

a2=a3-d

a2=24-6

a2=18

a1=a2-d

a1=18-6

a1=12