Answer:
The cost of admission to a popular music concert was $162$162 for 1212 children and 33 adults. The admission was $122$122 for 88 children and 33adults in another music concert. How much was the admission for each child and adult?
11 . Understand the problem:
The admission cost for 1212 children and 33 adults was $162$162 .
The admission cost for 88 children and 33 adults was $122$122 .
22 . Translate the problem to an equation.
Let xx represent the admission cost for each child.
Let yy represent the admission cost for each adult.
The admission cost for 1212 children plus 33 adults is equal to $162$162 .
That is, 12x+3y=16212x+3y=162 .
The admission cost for 8 children plus 3 adults is equal to $122.
That is, 8x+3y=1228x+3y=122 .
33 . Carry out the plan and solve the problem.
Subtract the second equation from the first.
12x+3y=162 8x+3y=122−−−−−−−−−−−− 4x = 40 x=1012x+3y=162 8x+3y=122_ 4x = 40 x=10
Substitute 1010 for xx in 8x+3y=1228x+3y=122 .
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