Answer:
[tex]\bold{\large{\mathtt{For \: Number \: One:}}}[/tex]
✓ The mathematical inequality represents the total amount Lovely paid is 600≥10x+3y.
[tex]x = cost \: of \: rice \\ y = cost \: of \: fish[/tex]
[tex]\bold{\large{\mathtt{For \: Number \: Two :}}}[/tex]
✓ The greatest cost of a kilo of fish to the nearest peso if a kilo of rice cost 35 pesos is Php. 83.00
[tex]600 \geqslant 10x+3y \\ 600 = 10(35) + 3y \\ 600 = 350 + 3y \\ 3y = 600 - 350 \\ 3y = 250 \\ y = 83.33[/tex]
> Rounding off 83.33 to the nearest pesos will be 83 since the number next to the decimal point is 3 which is less than 5.
[tex]\bold{\large{\mathtt{For \: Number \: Three:}}}[/tex]
✓ The least cost of a kilo of fish to the nearest peso if a kilo of rice cost 34 pesos and she paid more than 600 is Php. 84.00.
[tex]600>10x+3y \\ 601 = 10(34) + 3y \\ 601 = 340 + 3y \\ 3y = 601 - 350 \\ 3y = 251 \\ y = 83.67[/tex]
> The term used is more than 600 but the least cost. Therefore, you'll think of a number that is greater than and closest to 600, that'll be 601.
[tex]\blue{\bold{\large{\mathtt{MATH \: IS \: FUN!}}}} \\ \bold{\large{\mathtt{MODULE \: WELL!}}}[/tex]
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