Given:
[tex]P₁ = \text{560 to rr}[/tex]
[tex]V₁ = \text{145 m L}[/tex]
[tex]V₂ = \text{290 m L}[/tex]
Required:
[tex]P₂[/tex]
Solution:
[tex]P₁V₁ = P₂V₂[/tex]
[tex]P₂ = P₁ × \frac{V₁}{V₂}[/tex]
[tex]P₂ = \text{560 to rr} × \frac{\text{145 m L}}{\text{290 m L}}[/tex]
[tex]\boxed{P₂ = \text{280 to rr}}[/tex]
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