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If x varies jointly as y and z3, and x = 1,215 when y = 5 and z = 3, find x when y = 6 and z = 4.

Sagot :

Answer:

= 1,944

Step-by-step explanation:

y= kyz

when:

varies jointly is =

k= constant; we used k if possible in the problem

X2=?

(X2/X1)=(Y2/Y1)(Z2/Z1)

(X2/1,215)= (6/5)(4/3)

X2= 1,944