Answer:
suppose f(x)=6/5-x^3
calculate the exact value of x when f(x)=6
so: 6=6/5-x^3
6=6(5-x^3)
6=30-6x^3
-6x^3=6-30
-6x^3=-24
-6x^3+24=0
6x^3-24=0
6(x^3-4)=0
x^3-4=0
x^3=4
x=cube root 4
x=1.5874
needs to be a fraction form
but x=4/3
i dont know the answer
Step-by-step explanation:
sorry
