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a compound has 28.57% Na and 71.43% CI find the empirical formula of the compound?​

Sagot :

Answer:

Divide by fractional component of each mole value: Cl=4.2806343750606, Na=2.6403171875303

Divide by fractional component of each mole value: Cl=4.2806343750606, Na=2.64031718753037 Round to closest whole numbers: Cl=4, Na=3

Divide by fractional component of each mole value: Cl=4.2806343750606, Na=2.64031718753037 Round to closest whole numbers: Cl=4, Na=38 Combine to get the empirical formula: Cl4Na3

Explanation:

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