MIXTURE PROBLEM
QUESTION
- How many liters of 9% salt solution must be added to a 15% salt solution to get 25L of 12% salt solution?
SOLUTION
Let L = liters
x = unknown variable
Equation 1:
- 12% of 25L = N
- 0.12 x 25L = 3L
Keep in mind that if we add a 9% solution to 15% salt solution , The result should be 3L.
Forming an equation to the given problem:
- 9%L + 15% (x) = 25L x 12%
Solution to the equation
- 9%L + 15%x = 25L x 12%
- 0.09L + 0.15x = 3L
- 0.15x = 3L - 0.09L
- 0.15x = 2.91
- x = 2.91 ÷ 0.15
- x = 19.4L
Checking:
- 9%L + 15%(19.4L) = 25L x 12%
- 0.09L + 2.91L = 25L x 0.12
- 3L = 3L ✔️
ANSWER
- 19.4 Liters should be added to get a 25L of 12% solution.
#CarryOnLearning
