Answer:
1. Factor
2.
Step-by-step explanation:
1. Sbstitue - 5 (it became negative 5 merely because when we get the value of x in the divisor x+5,x+5=0, thenx=-5) to x in the quadratic function, when it ends with zero then it is a factor, but if its nonzero then its not a factor
[tex] {x}^{2} + 10x + 25 \\ { (- 5)}^{2} + (10)( - 5) + 25 \\ 25 - 50 + 25 \\ 0[/tex]
Therefore, the divisor (x+5) is a factor
2. Same thru with number two, substitute - 5 to x in the qutratic function
