Answer:
0
Step-by-step explanation:
f(a) = 3a + [tex]4a^{2}[/tex] - 10 = [tex]4a^{2}[/tex] + 3a - 10
f(-2) = [tex]4(-2)^{2}[/tex] + 3(-2) - 10 = 16 - 6 - 10 = 0
Answer:
0
Step-by-step explanation:
[tex]\rm 3a + 4a^2- 10[/tex]
Given:
Substitute the value of a in the expression.
[tex]\rm 3(-2) + 4(-2^2) - 10[/tex]
[tex]\implies -6 + 4(4) - 10[/tex]
[tex]\implies -6 + 16 - 10[/tex]
[tex]\implies 10 -10[/tex]
[tex]\implies \boxed{0}[/tex]
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