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The segments of one of two intersecting chords are x+2 and x+6, and x-4 and x+18 fot the other chord. find the length of each cord​

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Answer:

the length of each chords are 780 and 840.

Step-by-step explanation:

remember: intersecting chords. a1 a2=b1 b2

given:

chord 1: x+2, x+6

chord 2: x-4, x+18

let a1 be x+2

let a2 be x+6

let b1 be x-4

let b2 be x+18

a1 a2 = b1 b2

(x+2)(x+6) = (x-4)(x+18)

x²+6x+2x+12 = x²+18x-4x-72

x² + 8x + 12 = x² + 14x - 72

12+72 = x²-x² + 14x-8x

84 = 6x

24 = x

chord 1:

(x+2)(x+6)

(24+2)(24+6)

(26)(30)

780

chord 2:

(x-4)(x+18)

(24-4)(24+18)

(20)(42)

840

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