Sagot :
Problem:
y varies inversely as x, and x = 3 when y = 8, what is the value of x when y = 48?
Solution:
y = k/x
8 = k/3
8(3) = k
k = 24
y = k/x
xy = k
x = k/y
x = 24/48
x = 1/2
y = k/x
8 = k/3
8(3) = k
k = 24
y = k/x
xy = k
x = k/y
x = 24/48
x = 1/2