Sagot :
Answer:
To make your concept clear about such type of questions, you need to understand the concept of latent heat and sensible heat.
To make your concept clear about such type of questions, you need to understand the concept of latent heat and sensible heat.Latent Heat: The heat required to convert a solid into a liquid or vapour (latent heat of fusion), or a liquid into a vapour(latent heat of evaporation), without change of temperature.
To make your concept clear about such type of questions, you need to understand the concept of latent heat and sensible heat.Latent Heat: The heat required to convert a solid into a liquid or vapour (latent heat of fusion), or a liquid into a vapour(latent heat of evaporation), without change of temperature.Sensible Heat: The heat required to change the temperature of a body without changing its phase.
To make your concept clear about such type of questions, you need to understand the concept of latent heat and sensible heat.Latent Heat: The heat required to convert a solid into a liquid or vapour (latent heat of fusion), or a liquid into a vapour(latent heat of evaporation), without change of temperature.Sensible Heat: The heat required to change the temperature of a body without changing its phase.So, basically as your question suggests, you need to evaluate the heat required to convert 2 kg of ice at 0 °C to water at 20 °C.. the total heat content will comprise of:
To make your concept clear about such type of questions, you need to understand the concept of latent heat and sensible heat.Latent Heat: The heat required to convert a solid into a liquid or vapour (latent heat of fusion), or a liquid into a vapour(latent heat of evaporation), without change of temperature.Sensible Heat: The heat required to change the temperature of a body without changing its phase.So, basically as your question suggests, you need to evaluate the heat required to convert 2 kg of ice at 0 °C to water at 20 °C.. the total heat content will comprise of:Total heat = Heat required to convert 2 kg of ice to 2 kg of water at 0 °C + Heat required to convert 2 kg of water at 0 °C to 2 kg of water at 20 °C.
To make your concept clear about such type of questions, you need to understand the concept of latent heat and sensible heat.Latent Heat: The heat required to convert a solid into a liquid or vapour (latent heat of fusion), or a liquid into a vapour(latent heat of evaporation), without change of temperature.Sensible Heat: The heat required to change the temperature of a body without changing its phase.So, basically as your question suggests, you need to evaluate the heat required to convert 2 kg of ice at 0 °C to water at 20 °C.. the total heat content will comprise of:Total heat = Heat required to convert 2 kg of ice to 2 kg of water at 0 °C + Heat required to convert 2 kg of water at 0 °C to 2 kg of water at 20 °C.Heat=mhfg+mCpΔTHeat=mhfg+mCpΔT
To make your concept clear about such type of questions, you need to understand the concept of latent heat and sensible heat.Latent Heat: The heat required to convert a solid into a liquid or vapour (latent heat of fusion), or a liquid into a vapour(latent heat of evaporation), without change of temperature.Sensible Heat: The heat required to change the temperature of a body without changing its phase.So, basically as your question suggests, you need to evaluate the heat required to convert 2 kg of ice at 0 °C to water at 20 °C.. the total heat content will comprise of:Total heat = Heat required to convert 2 kg of ice to 2 kg of water at 0 °C + Heat required to convert 2 kg of water at 0 °C to 2 kg of water at 20 °C.Heat=mhfg+mCpΔTHeat=mhfg+mCpΔT Here, m ( mass of ice) = 2 kg
hfg (latent heat of fusion of ice) = 334 KJ
hfg (latent heat of fusion of ice) = 334 KJCp of water (specific heat) = 4.187 KJ/Kg-K
hfg (latent heat of fusion of ice) = 334 KJCp of water (specific heat) = 4.187 KJ/Kg-KΔT(Temperature difference) = 20 °C
hfg (latent heat of fusion of ice) = 334 KJCp of water (specific heat) = 4.187 KJ/Kg-KΔT(Temperature difference) = 20 °CTherefore, Heat required = 2 x 334 + 2 x 4.187 x (20 - 0 )
hfg (latent heat of fusion of ice) = 334 KJCp of water (specific heat) = 4.187 KJ/Kg-KΔT(Temperature difference) = 20 °CTherefore, Heat required = 2 x 334 + 2 x 4.187 x (20 - 0 )Heat reqd= 835.48 KJ
hfg (latent heat of fusion of ice) = 334 KJCp of water (specific heat) = 4.187 KJ/Kg-KΔT(Temperature difference) = 20 °CTherefore, Heat required = 2 x 334 + 2 x 4.187 x (20 - 0 )Heat reqd= 835.48 KJTherefore, to melt 2 kg of ice 835.48 KJ of heat is required.
hfg (latent heat of fusion of ice) = 334 KJCp of water (specific heat) = 4.187 KJ/Kg-KΔT(Temperature difference) = 20 °CTherefore, Heat required = 2 x 334 + 2 x 4.187 x (20 - 0 )Heat reqd= 835.48 KJTherefore, to melt 2 kg of ice 835.48 KJ of heat is required.Happy Reading!