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Answered

How much heat must be added to 5.5 g of ice at 0℃ to become water at 10℃?

Sagot :

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Answer:

27.5 calories

Explanation:

Specific Heat Theorem:

Q=mc∆T

m= mass

c = specific heat; where ice is a constant of = 0.5cal/g-°c

∆T= T2 - T1

(5.5g)(0.5cal/g-°C)(10°C - 0°C)

=27.5 calories

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