Answer:
[tex]15[/tex]
Solution:
[tex]\bold{f(x)=1+\sqrt{x^{2} } +3x+6 \ }\\\\\bold{Since \ "x = 2" \ Simply \ Substitute \ The \ Given \ Values.}\\\\f(x)=1+\sqrt{x^{2} } +3x+6\\\\f(x)=1+\sqrt{2^{2} } +3(2)+6\\\\f(x)=1+\sqrt{4} +6+6\\\\f(x)=1+2 +6+6\\\\f(x)=[(1+2) +6]+6\\\\f(x)=[(3+6)+6]\\\\f(x) = 9 + 6\\\\ f(x) = 15\\\\\boxed{f(x) = 15}[/tex]
(Note: I placed brackets "[]" and parenthesis "()" so that it would be easier to understand)
(Remember: When encountering this kind of problem, all you need to do is to "Substitute" the given values.)
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