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Determine a value for ∆ which will make each statement true.


a. x∆ . x⁷ = x12

=

b. (3×⁵) ∆ = 27×¹⁵


=




Sagot :

Answer:

1) ∆ = 5

2) ∆ = 9x¹⁰

Step-by-step explanation:

You simply have to add the EXPONENTS such that:

a) x∆ • x⁷ = x¹²

Let N be ∆,

exponent: N+7 = 12

N = 12-7

∆ = 5

x⁵ • x⁷ = x¹²

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b) (3x⁵)∆ = 27x¹⁵

Let N be ∆,

base: 3x • N = 27x

N = 27x/3x

N = 9x

exponent: 5+N = 15

N = 15-5

N = 10

∆ = 9x¹⁰

(3x⁵)9x¹⁰ = 27x¹⁵