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HELP ME PLEASE IN MY MODULE MATH ANSWER THIS PLEASE

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АНОНИМIN АНОНИМIN · Answer 1

АНОНИМIN АНОНИМIN

Answer:

1) 3 4/5

2) 4 3/5

3) 2 1/6

4) 3 10/13

5) 3 11/20

1) 23/3

2) 46/5

3) 27/4

4) 23/7

5) 71/12

1) 2/3

2) 4/5

3) 2/13

4) 2/3

5) 6/7

1) 3/5

2) 7/11

3) 3/4

4) 2/3

5) 3/5

Step-by-step explanation:

Hope it helps you

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KCPARIS10IN KCPARIS10IN · Answer 2

Answer:

I. Change the following improper fractions to mixed numbers.

1. 19/5= 3 4/5 3. 13/6= 2 1/6 5. 71/20= 3 11/20

2. 23/5= 4 3/5 4. 49/13= 3 13/10

II. Change the following numbers to improper fractions.

1. 7 2/3= 23/3 3. 6 3/4= 27/4 5. 5 11/2= 21/2

2. 9 1/5= 46/5 4. 3 2/7= 24/7

III. Write each fraction in lowest terms.

1. 14/21= 2/3 3. 6/39= 2/13 5. 36/42= 18/21= 6/7

2. 18/20= 9/10 4. 22/33= 2/3

IV. Find the sum. Express the answer in lowest terms.

1. 2/5 + 1/5= 3/5 3. 2/8 + 3/8 +1/8= 6/8= 3/4

2. 5/11 + 2/11= 7/11 4. 3/9 + 1/9 + 2/9= 6/9= 2/3

5. 6/20 +2/20+ 4/20= 12/20= 6/10= 3/5

Step-by-step explanation:

I. divide 19 in 5. You get 3 remainder 4. The denominator should be five and the numerator should be four and 3 will become a whole number (3 4/5). Repeat this solution.

II. Multiply 7 and 3 then add 2. The denominator should be 3 and the numerator should be 23 (23/3). Repeat this solution.

III. Find the number that can be divided to both the denominator and numerator. Repeat this solution, with the other given.

IV. Add the numerator and the denominator is still the same. If its improper, do the solution I gave in the III. Repeat this solution.

Hope I helped you. Just think carefully and you'll reach your goals in life.