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A spring whose spring constant is 6 N/m is stretching 0.7 m from its equilibrium position.
What is the increase in elastic potential energy?​

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Calculating the spring force

Given

  • Spring Constant (k) = 6 N/m
  • Displacement (x) = 0.7 m
  • Spring Force (F) = ?

Using Hooke's Law, we can calculate the spring force.

F = kx

F = (6 N/m)(0.7 m)

F = 4.2 N

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