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If 3,600 basketball shorts are distributed to four sports houses in the ratio of 1:2:3:4, how many shorts does the sports house with the largest share receive​

Sagot :

The sports house with the largest share received 1,440 shorts.

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Step-by-step explanation:

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Given:

Let n be the total number of basketball shorts, n = 3,600

Ratio is 1:2:3:4

Let x be the number of shorts the first sports house received

Let 2x be the number of shorts the second sports house received

Let 3x be the number of shorts the third sports house received

Let 4x be the number of shorts the fourth sports house received

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Required:

Number of shorts the sports house with the largest share received

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Equation:

n = x + 2x + 3x + 4x

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Solution/Calculation:

Find the value of x

Substitute the value of n which is 3,600

n = x + 2x + 3x + 4x

3,600 = x + 2x + 3x + 4x

3,600 = 10x

x = [tex]\frac{3,600}{10}[/tex]

x = 360

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Find the number of shorts the first sports house received

= x

= 360

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Find the number of shorts the second sports house received

= 2x

= 2(360)

= 720

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Find the number of shorts the first sports house received

= 3x

= 3(360)

= 1,080

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Find the number of shorts the fourth sports house received

= 4x

= 4(360)

= 1,440

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Checking:

n = x + 2x + 3x +4x

3600 = 360 + 720 + 1,080 + 1,440

3600 = 3600 ✓

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Answer:

The sports house with the largest share received 1,440 shorts.

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