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the product of two decimal numbers is 0.32 one number is one half of the other​

Sagot :

Answer:

y=0.8

x=0.4

Explanation:

Let x and y be the two unknown decimal numbers

xy=0.32

[tex]x=\frac{1}{2} y[/tex]

Substitute the value of x

([tex]\frac{1}{2} y[/tex])(y)=0.32

[tex]\frac{1}{2} y^{2}[/tex]=0.32

[tex]y^{2}[/tex]=0.64

y=0.8

x= [tex]\frac{1}{2} (0.8)[/tex]

x=0.4

Answer:x=0.8;y=0.4

Step-by-step explanation:

x*y=0.32

y=0.5x

x(0.5x)=0.32

0.5x^2=0.32

x^2=0.32/0.5=0.64

x=0.8

checking

xy=0.32

(0.8)[(0.5)(0.8)]=0.32

(0.8)(0.4)=0.32

0.32=0.32