Sagot :
Answer:
[tex]6x - {2x}^{2} - 1 = 8 \\ 6x - {2x}^{2} - 1 - 8 = 0[/tex]
[tex] { - 2x}^{2} + 6x - 9 = 0[/tex]
since first term is ≠ 0 . . .
[tex] - 1( { - 2x}^{2} + 6x - 9 = 0) \\ \\ {2x}^{2} - 6x + 9 = 0[/tex]
Answer:
[tex]6x - {2x}^{2} - 1 = 8 \\ 6x - {2x}^{2} - 1 - 8 = 0[/tex]
[tex] { - 2x}^{2} + 6x - 9 = 0[/tex]
since first term is ≠ 0 . . .
[tex] - 1( { - 2x}^{2} + 6x - 9 = 0) \\ \\ {2x}^{2} - 6x + 9 = 0[/tex]