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A 130-lb woman balances on the heel of one shoe,which is 1 in. in radius. How much pressure does she exert on the floor?​

Sagot :

Converting the mass from lb to kg.

1 lb = 0.454 kg

(130 lb)(0.454 / 1 lb)

= 59.02 kg

Calculating the force excerted.

Given

  • Mass (m) = 59.02 kg
  • Acceleration (a) = 9.8 m/s²
  • Force (F) = ?

F = ma

F = (59.02)(9.8)

F = 578.396 N

Converting the radius from in. to m.

1 in = 0.0254 m

(1 in)(0.0254 m / 1 in)

= 0.0254 m

Calculating the area of the heel of the shoe.

Assuming the shape of the heel is a circle

Given

  • Radius (r) = 0.0254 m
  • Area (A) = ?

Use π = 3.14

A = πr²

A = (3.14)(0.0254)²

A = (3.14)(6.4516 x 10⁻⁴)

A = 2.0258 x 10³ m²

Calculating the pressure of the heel.

Given

  • Force (F) = 578.396 N
  • Area (A) = 2.0258 x 10⁻³ m²
  • Pressure (P) = ?

P = F / A

P = 578.396 N / 2.0258 x 10⁻³ m²

P = 285514 Pa or 0.29 mPa

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