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Math

Answered

What is the value of 3x²y³c when x=3,y=-2 and c=1/3

paki sagot naman po

Sagot :

AZB694IN AZB694IN

Answer:

-48

Step-by-step explanation:

3x^2y^3c

= 3(3)^2 (-2)^3 (1/3)

=3(6)(-8)(1/3)

multiply all the numbers

= -48

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