Answer:
Consider a △ABC, then according to the given condition we have:
∠A+∠B= 90° and ∠A−∠B= 20°
⇒2∠A=90°
⇒∠A=45°
⇒∠B=45°
Using the sum of all the angles of the triangle is 180°
We have: ∠A+∠B+∠C=180°
⇒45°+ 45° +∠C = 180°
⇒∠C=90
Hence ∠A=45°, ∠B=45°, and ∠C=90°
Step-by-step explanation:
∠A=45° + ∠B=45° + ∠C=90° = 180°
