Problem:
z varies jointly as x and y,and inversely as t,if z=12,k=3,y=20 and t=5,find z if x=15,y=14 and t=8
Solution:
k = constant of variation
z = kxy/t
12 = k(3)(20)/5
12(5) = 60k
60/60=k
k = 1
z = kxy/t
z = 1(15)(14)/8
z = 210/8
z = 105/4
z = 26.25
#CarryOnLearning
